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Question Number 113262 by bemath last updated on 12/Sep/20
find the complex form of   equation 4x^2 −2y^2 =5
findthecomplexformofequation4x22y2=5
Answered by mr W last updated on 12/Sep/20
(x^2 /((((√5)/2))^2 ))−(y^2 /((((√5)/( (√2))))^2 ))=1  c^2 =a^2 +b^2 =(5/4)+(5/2)=((15)/4)  c=((√(15))/2)  it′s a hyperbola with foci (−((√(15))/2),0)  and (((√(15))/2),0) as well as semi major  axis a=((√5)/2).  according to the definition of  hyperbola we can write its equation  also in complex form:  ∣z+c∣−∣z−c∣=±2a  or  ∣z+((√(15))/2)∣−∣z−((√(15))/2)∣=±(√5)
x2(52)2y2(52)2=1c2=a2+b2=54+52=154c=152itsahyperbolawithfoci(152,0)and(152,0)aswellassemimajoraxisa=52.accordingtothedefinitionofhyperbolawecanwriteitsequationalsoincomplexform:z+czc∣=±2aorz+152z152∣=±5
Commented by mr W last updated on 12/Sep/20
certainly you can also write the  equation in many other complex forms.
certainlyyoucanalsowritetheequationinmanyothercomplexforms.
Commented by bemath last updated on 12/Sep/20
thank you sir
thankyousir
Answered by john santu last updated on 12/Sep/20
let z = x+iy and z^−  = x−iy    { ((z+z^−  = (2x,0); x = ((z+z^− )/2))),((z−z^−  = (0, 2y); y=((z−z^− )/2))) :}  ⇔ 4x^2 −2y^2 =5 in complex form   4(((z+z^− )/2))^2 −2(((z−z^− )/2))^2 = 5  (z+z^− )^2 −(((z−z^− )^2 )/2) = 5   2(z+z^− )^2 −(z−z^− )^2  = 10
letz=x+iyandz=xiy{z+z=(2x,0);x=z+z2zz=(0,2y);y=zz24x22y2=5incomplexform4(z+z2)22(zz2)2=5(z+z)2(zz)22=52(z+z)2(zz)2=10

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