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find-the-derivative-of-1-x-3x-8-sin-2-1-5x-1-4-plzzz-help-




Question Number 24911 by chernoaguero@gmail.com last updated on 28/Nov/17
find the derivative of   ((((1−x)(√(3x−8)))/(sin^2 (1−5x))))^(1/4)   plzzz help
$$\mathrm{find}\:\mathrm{the}\:\mathrm{derivative}\:\mathrm{of}\: \\ $$$$\sqrt[{\mathrm{4}}]{\frac{\left(\mathrm{1}−\mathrm{x}\right)\sqrt{\mathrm{3x}−\mathrm{8}}}{\mathrm{sin}^{\mathrm{2}} \left(\mathrm{1}−\mathrm{5x}\right)}} \\ $$$$\mathrm{plzzz}\:\mathrm{help}\: \\ $$
Commented by chernoaguero@gmail.com last updated on 29/Nov/17
Plzzz help me with question its   givin me tough time
$$\mathrm{Plzzz}\:\mathrm{help}\:\mathrm{me}\:\mathrm{with}\:\mathrm{question}\:\mathrm{its}\: \\ $$$$\mathrm{givin}\:\mathrm{me}\:\mathrm{tough}\:\mathrm{time} \\ $$$$ \\ $$
Answered by jota+ last updated on 29/Nov/17
y^4 =(((1−x)(√(3x−8)))/(sin^2 (1−5x)))  4lny=ln (1−x)+0.5ln (3x−8)         −2ln (sin(1−5x)).  4(y^′ /y)=((−1)/(1−x)) + ((0.5×3)/(3x−8)) −((2cos(1−5x)(−5))/(sin(1−5x))).
$${y}^{\mathrm{4}} =\frac{\left(\mathrm{1}−{x}\right)\sqrt{\mathrm{3}{x}−\mathrm{8}}}{{sin}^{\mathrm{2}} \left(\mathrm{1}−\mathrm{5}{x}\right)} \\ $$$$\mathrm{4ln}{y}=\mathrm{ln}\:\left(\mathrm{1}−{x}\right)+\mathrm{0}.\mathrm{5ln}\:\left(\mathrm{3}{x}−\mathrm{8}\right)\: \\ $$$$\:\:\:\:\:\:−\mathrm{2ln}\:\left({sin}\left(\mathrm{1}−\mathrm{5}{x}\right)\right). \\ $$$$\mathrm{4}\left({y}^{'} /{y}\right)=\frac{−\mathrm{1}}{\mathrm{1}−{x}}\:+\:\frac{\mathrm{0}.\mathrm{5}×\mathrm{3}}{\mathrm{3}{x}−\mathrm{8}}\:−\frac{\mathrm{2}{cos}\left(\mathrm{1}−\mathrm{5}{x}\right)\left(−\mathrm{5}\right)}{{sin}\left(\mathrm{1}−\mathrm{5}{x}\right)}. \\ $$$$ \\ $$
Commented by chernoaguero@gmail.com last updated on 01/Dec/17
No sir thatz not d answer
$$\mathrm{No}\:\mathrm{sir}\:\mathrm{thatz}\:\mathrm{not}\:\mathrm{d}\:\mathrm{answer} \\ $$
Commented by jota+ last updated on 01/Dec/17
Subtitute y in terms x reduce and   ready.
$${Subtitute}\:{y}\:{in}\:{terms}\:{x}\:{reduce}\:{and}\: \\ $$$${ready}. \\ $$

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