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Question Number 83257 by 09658867628 last updated on 29/Feb/20
find the derivtive of y=((10^x )/(log_(10) x))
findthederivtiveofy=10xlog10x
Answered by TANMAY PANACEA last updated on 29/Feb/20
y=(u/v)→(dy/dx)=((v(du/dx)−u(dv/dx))/v^2 )  u=10^x →lnu=xln10  (1/u)(du/dx)=ln10 so (du/dx)=10^x ln10  v=log_(10) x so  v=((lnx)/(ln10))  (dv/dx)=(1/(xln10))  (dy/dx)=((log_(10) x.10^x ln10−10^x .(1/(xln10)))/((log_(10) x)^2 ))
y=uvdydx=vdudxudvdxv2u=10xlnu=xln101ududx=ln10sodudx=10xln10v=log10xsov=lnxln10dvdx=1xln10dydx=log10x.10xln1010x.1xln10(log10x)2

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