Menu Close

find-the-domain-and-range-of-y-1-x-1-x-2-restricted-to-0-x-6-




Question Number 181628 by Tawa11 last updated on 27/Nov/22
find the domain and range of   y  =  (1/((x  −  1)(x  +  2)))  restricted to   0  ≤  x  ≤  6
$$\mathrm{find}\:\mathrm{the}\:\mathrm{domain}\:\mathrm{and}\:\mathrm{range}\:\mathrm{of}\:\:\:\mathrm{y}\:\:=\:\:\frac{\mathrm{1}}{\left(\mathrm{x}\:\:−\:\:\mathrm{1}\right)\left(\mathrm{x}\:\:+\:\:\mathrm{2}\right)} \\ $$$$\mathrm{restricted}\:\mathrm{to}\:\:\:\mathrm{0}\:\:\leqslant\:\:\mathrm{x}\:\:\leqslant\:\:\mathrm{6} \\ $$
Answered by Acem last updated on 27/Nov/22
Commented by Acem last updated on 27/Nov/22
⊛ (1/0^( ±) )
$$\circledast\:\frac{\mathrm{1}}{\mathrm{0}^{\:\pm} } \\ $$
Commented by mr W last updated on 28/Nov/22
domain:  [0,6]−{1}  range:  (−∞,−(1/2)] ∩[(1/(40)),+∞)
$${domain}: \\ $$$$\left[\mathrm{0},\mathrm{6}\right]−\left\{\mathrm{1}\right\} \\ $$$${range}: \\ $$$$\left(−\infty,−\frac{\mathrm{1}}{\mathrm{2}}\right]\:\cap\left[\frac{\mathrm{1}}{\mathrm{40}},+\infty\right) \\ $$
Commented by Tawa11 last updated on 28/Nov/22
God bless you sirs.
$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sirs}. \\ $$

Leave a Reply

Your email address will not be published. Required fields are marked *