Find-the-equation-of-the-perpendicular-bisector-of-the-line-segment-joining-the-points-1-3-and-5-1-

Question Number 38880 by Rio Mike last updated on 30/Jun/18

F i n d t h e e q u a t i o n o f t h e p e r p e n d i c u l a r

b i s e c t o r o f t h e l i n e s e g m e n t j o i n i n g

t h e p o i n t s (1, 3) a n d (5, 1)

Answered by MrW3 last updated on 30/Jun/18

e q n o f l i n e j o i n i n g (1, 3) a n d (5, 1) :

\frac{y - 1}{3 - 1} = \frac{x - 5}{1 - 5}

y = - \frac{1}{2} (x - 5) + 1 = - \frac{1}{2} x + \frac{7}{2}

m i d p o i n t o f (1, 3) a n d (5, 1) :

(3, 2)

e q n . o f p e r p e n d i c u l a r b i s e c t o r :

\frac{y - 2}{x - 3} = - \frac{1}{- \frac{1}{2}} = 2

\Rightarrow y = 2 x - 4

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