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find-the-fourier-series-of-the-function-f-x-x-2-x-0-4-0-x-2-help-me-sir-




Question Number 100899 by mhmd last updated on 29/Jun/20
find the fourier series of the function f(x)= { ((x    −2≤x≤0   )),((4          0≤x≤2)) :}   ?  help me sir ?
findthefourierseriesofthefunctionf(x)={x2x040x2?helpmesir?
Answered by bramlex last updated on 29/Jun/20
f(x) : odd function. L = 4  a_n  = 0   b_n  = (2/L)∫_0 ^L  f(x)sin (((nπx)/L)) dx  b_n  = (2/4)[∫_(−2) ^0 x sin (((nπx)/4))dx+∫_0 ^2 4sin (((nπx)/4)) dx]   b_n =(1/2)[ ((16)/(n^2 π^2 ))sin (((nπ)/2))+(4/(nπ)) ]  b_n  = (8/((nπ)^2 )) sin (((nπ)/2)) + (2/(nπ))  f(x)=(a_0 /2) + Σ_(n=1) ^∞ [(8/((nπ)^2 )) sin (((nπ)/2))+(2/(nπ)) ]. cos (((nπx)/4))
f(x):oddfunction.L=4an=0bn=2LL0f(x)sin(nπxL)dxbn=24[02xsin(nπx4)dx+204sin(nπx4)dx]bn=12[16n2π2sin(nπ2)+4nπ]bn=8(nπ)2sin(nπ2)+2nπf(x)=a02+n=1[8(nπ)2sin(nπ2)+2nπ].cos(nπx4)
Commented by mhmd last updated on 29/Jun/20
sir can you send the all solution ?
sircanyousendtheallsolution?
Commented by mhmd last updated on 29/Jun/20
thank you sir
thankyousir

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