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Find-the-function-whose-first-derivative-is-8-5-x-2-1-3-the-initial-conditions-f-8-20-




Question Number 50161 by cesar.marval.larez@gmail.com last updated on 14/Dec/18
Find the function whose first   derivative is 8−(5/( (x^2 )^(1/3) )) the initial   conditions f(8)=−20
Findthefunctionwhosefirstderivativeis85x23theinitialconditionsf(8)=20
Answered by afachri last updated on 14/Dec/18
F(x)  =  ∫ f′(x)  dx                =  ∫  8 − 5x^(−(2/3)) dx                =  8x  −  ((5/((−(2/3)+1))))x^(−(2/3)+1)  +  C                =  8x −  15x^(1/3)  + C  to find C:                                         F(8)  =  −20  8(8)  −  15(8)^(1/3)  +  C  =  −20                  64  −  30  +  C  =  −20                                                C  =  −54    So  :  F(x)  =  8x  −  15x^(1/3) −  54
F(x)=f(x)dx=85x23dx=8x(5(23+1))x23+1+C=8x15x13+CtofindC:F(8)=208(8)15(8)13+C=206430+C=20C=54So:F(x)=8x15x1354
Commented by cesar.marval.larez@gmail.com last updated on 14/Dec/18
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Commented by afachri last updated on 14/Dec/18
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itsbeenourpleasure

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