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Question Number 89867 by M±th+et£s last updated on 19/Apr/20
find the integration  ∫ln⌊x⌋ dx      ; x>2
findtheintegrationlnxdx;x>2
Commented by ~blr237~ last updated on 20/Apr/20
Answered by mr W last updated on 20/Apr/20
let x=n+f  dx=df  ∫ln ⌊x⌋dx=ln n ∫df=(ln n)f+C  =(ln ⌊x⌋)(x−⌊x⌋)+C
letx=n+fdx=dflnxdx=lnndf=(lnn)f+C=(lnx)(xx)+C
Commented by M±th+et£s last updated on 20/Apr/20
sir why ∫ln⌊x⌋dx=ln(n)∫df  and how  did you get ln(⌊x⌋)(x−⌊x⌋)
sirwhylnxdx=ln(n)dfandhowdidyougetln(x)(xx)
Commented by mr W last updated on 21/Apr/20
x=n+f with n=⌊x⌋, f=x−⌊x⌋  in x=n+f, n is constant, therefore  dx=df  ∫ln ⌊x⌋dx=∫(ln n)df=ln (n)∫df  =ln (n)f+C  =(ln ⌊x⌋)(x−⌊x⌋)+C
x=n+fwithn=x,f=xxinx=n+f,nisconstant,thereforedx=dflnxdx=(lnn)df=ln(n)df=ln(n)f+C=(lnx)(xx)+C
Commented by M±th+et£s last updated on 21/Apr/20
thank you for explaing that for me
thankyouforexplaingthatforme
Answered by M±th+et£s last updated on 22/Apr/20
i try a lot and i get that  ln[x]dx=ln(2)    x∈(2,3)  f(x)=ln[x] x∈(n,n+1)  ∫ln[x]dx=Σ_(k=2) ^(n−1) ln(x) + ∫_(n=[x]) ^x ln[x]dx  Σ_(k=2) ^(n−1) ln(k)+ln(n)(x−[x])+c
itryalotandigetthatln[x]dx=ln(2)x(2,3)f(x)=ln[x]x(n,n+1)ln[x]dx=n1k=2ln(x)+n=[x]xln[x]dxn1k=2ln(k)+ln(n)(x[x])+c

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