Menu Close

Find-the-non-negative-integer-solutions-of-2x-3y-5z-60-




Question Number 163313 by SLVR last updated on 06/Jan/22
Find the non negative integer  solutions of 2x+3y+5z=60
Findthenonnegativeintegersolutionsof2x+3y+5z=60
Answered by mr W last updated on 06/Jan/22
let 2x+3y=5u  5u+5z=60  u+z=12  ⇒u=n with n ∈ Z  ⇒z=12−n    2x+3y=1  x=3k−1 with k ∈ Z  y=−2k+1  2x+3y=5u=5n  x=5n(3k−1)=3(5nk)−5n=3m−5n  y=5n(−2k+1)=−2(5nk)+5n=−2m+5n    general solution:   { ((x=3m−5n)),((y=−2m+5n)),((z=12−n)) :}     (with m,n∈Z)  non−negative solutions:  z=12−n≥0 ⇒n≤12  x=3m−5n≥0  y=−2m+5n≥0  ⇒0≤n≤12  ⇒((5n)/3)≤m≤((5n)/2)  totally there are 71 solutions:  n=0: m=0  n=1: m=2  n=2: m=3, 4  n=3: m=5, 6, 7  ....  n=12: m=20, 21, ..., 30
let2x+3y=5u5u+5z=60u+z=12u=nwithnZz=12n2x+3y=1x=3k1withkZy=2k+12x+3y=5u=5nx=5n(3k1)=3(5nk)5n=3m5ny=5n(2k+1)=2(5nk)+5n=2m+5ngeneralsolution:{x=3m5ny=2m+5nz=12n(withm,nZ)nonnegativesolutions:z=12n0n12x=3m5n0y=2m+5n00n125n3m5n2totallythereare71solutions:n=0:m=0n=1:m=2n=2:m=3,4n=3:m=5,6,7.n=12:m=20,21,,30
Commented by SLVR last updated on 06/Jan/22
Wow...really great enough..we  are blessed...with your service
Wowreallygreatenough..weareblessedwithyourservice
Commented by mr W last updated on 06/Jan/22
Commented by mr W last updated on 06/Jan/22
note:  number of non negative solutions of  2x+3y+5z=60 is the coef. of term x^(60)   in the expansion of   (1+x^2 +x^4 +...)(1+x^3 +x^6 +...)(1+x^5 +x^(10) +...)  =(1/((1−x^2 )(1−x^3 )(1−x^5 ))). that is 71.
note:numberofnonnegativesolutionsof2x+3y+5z=60isthecoef.oftermx60intheexpansionof(1+x2+x4+)(1+x3+x6+)(1+x5+x10+)=1(1x2)(1x3)(1x5).thatis71.
Commented by mr W last updated on 06/Jan/22
Commented by Rasheed.Sindhi last updated on 06/Jan/22
M RE _(THAN_(P∈RF∈⊂T  !) )   Multimedia(graph)  & number of solutions    are  in addition!  ThanX sir!
MRETHANPRF∈⊂T!Multimedia(graph)&numberofsolutionsareinaddition!ThanXsir!
Commented by mr W last updated on 06/Jan/22
thanks sirs!  graph helps very much to find out if   errors are made. therefore i like to   work with graph.
thankssirs!graphhelpsverymuchtofindoutiferrorsaremade.thereforeiliketoworkwithgraph.
Commented by Tawa11 last updated on 06/Jan/22
Great sir
Greatsir
Commented by Rasheed.Sindhi last updated on 07/Jan/22
SHARING: https://youtu.be/fw1kRz83Fj0
Commented by SLVR last updated on 31/Jan/22
Respected prof.W...evaluation  of x^(60)  with out original mul  tlication all terms complnent  wise..kindly  with general  term of expansion.please
Respectedprof.Wevaluationofx60withoutoriginalmultlicationalltermscomplnentwise..kindlywithgeneraltermofexpansion.please
Commented by mr W last updated on 31/Jan/22
please express clearly what you want  to have!
pleaseexpressclearlywhatyouwanttohave!
Commented by SLVR last updated on 02/Feb/22
Sir...I mean to say ..  coeffitient of x^(60)  in (1−x^2 )(1−x^3 )(1−x^5 )  not by multiplying all terms  but possibility of general term of(1−x)^(−1)   C_r ^(n+r−1)  ... Or getting the coeffitient  of x^(60)   as 71 in a easy way???  Please..sir...
SirImeantosay..coeffitientofx60in(1x2)(1x3)(1x5)notbymultiplyingalltermsbutpossibilityofgeneraltermof(1x)1Crn+r1Orgettingthecoeffitientofx60as71inaeasyway???Please..sir
Commented by mr W last updated on 02/Feb/22
in fact there is no easy way to   determine the coefficient of a   general term.
infactthereisnoeasywaytodeterminethecoefficientofageneralterm.

Leave a Reply

Your email address will not be published. Required fields are marked *