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Question Number 101880 by mr W last updated on 05/Jul/20
Find the number of six−digit odd  numbers without repeated digits.
$${Find}\:{the}\:{number}\:{of}\:{six}−{digit}\:{odd} \\ $$$${numbers}\:{without}\:{repeated}\:{digits}. \\ $$
Answered by bemath last updated on 05/Jul/20
5×8×C_4 ^8 ×4!
$$\mathrm{5}×\mathrm{8}×{C}_{\mathrm{4}} ^{\mathrm{8}} ×\mathrm{4}! \\ $$
Commented by mr W last updated on 05/Jul/20
correct, thanks!
$${correct},\:{thanks}! \\ $$
Answered by som(math1967) last updated on 05/Jul/20
Odd numbers unitdigit 1  p_5 ^9 − ^8 p_4 =9×8×7×6×5−8×7×6×5  =8×7×6×5(9−1)  =8×7×6×40  ∴total odd numbers=56×240×5  =67200
$$\mathrm{Odd}\:\mathrm{numbers}\:\mathrm{unitdigit}\:\mathrm{1} \\ $$$$\overset{\mathrm{9}} {\mathrm{p}}_{\mathrm{5}} −\overset{\mathrm{8}} {\:}\mathrm{p}_{\mathrm{4}} =\mathrm{9}×\mathrm{8}×\mathrm{7}×\mathrm{6}×\mathrm{5}−\mathrm{8}×\mathrm{7}×\mathrm{6}×\mathrm{5} \\ $$$$=\mathrm{8}×\mathrm{7}×\mathrm{6}×\mathrm{5}\left(\mathrm{9}−\mathrm{1}\right) \\ $$$$=\mathrm{8}×\mathrm{7}×\mathrm{6}×\mathrm{40} \\ $$$$\therefore\mathrm{total}\:\mathrm{odd}\:\mathrm{numbers}=\mathrm{56}×\mathrm{240}×\mathrm{5} \\ $$$$=\mathrm{67200} \\ $$
Commented by som(math1967) last updated on 05/Jul/20
welcome sir
$$\mathrm{welcome}\:\mathrm{sir} \\ $$
Commented by mr W last updated on 05/Jul/20
correct, thanks!
$${correct},\:{thanks}! \\ $$

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