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find-the-number-of-solutions-of-6-cos-x-7sin-2-x-cos-x-0-




Question Number 144329 by gsk2684 last updated on 24/Jun/21
find the number of solutions   of (√(6−cos x+7sin^2 x))+cos x=0
findthenumberofsolutionsof6cosx+7sin2x+cosx=0
Commented by MJS_new last updated on 25/Jun/21
let c=cos x ⇒ −1≤c≤1  (√(13−c−7c^2 ))+c=0 ⇒ c<0  (√(13−c−7c^2 ))=−c  13−c−7c^2 =c^2   8c^2 +c−13=0∧c<0  ⇒ c=−((1+(√(417)))/(16))<−1  ⇒ no solution    [−1+(√7)≤(√(6−cos x +7sin^2  x))+cos x ≤((−1+2(√(730)))/(14))]
letc=cosx1c113c7c2+c=0c<013c7c2=c13c7c2=c28c2+c13=0c<0c=1+41716<1nosolution[1+76cosx+7sin2x+cosx1+273014]
Commented by gsk2684 last updated on 25/Jun/21
thank you mr MJS
thankyoumrMJS

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