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Find-the-oxidation-number-of-the-underlined-element-in-the-following-a-KCl-O-3-b-SO-3-2-c-H-2-SO-4-d-Na-H-




Question Number 177725 by Spillover last updated on 08/Oct/22
Find the oxidation number of the  underlined element in the   following  (a)KCl O_3   (b)SO_3 ^(2−)   (c)H_2 SO_4   (d)Na H
$$\mathrm{Find}\:\mathrm{the}\:\mathrm{oxidation}\:\mathrm{number}\:\mathrm{of}\:\mathrm{the} \\ $$$$\mathrm{underlined}\:\mathrm{element}\:\mathrm{in}\:\mathrm{the} \\ $$$$\:\mathrm{following} \\ $$$$\left(\mathrm{a}\right)\mathrm{K}\underline{\boldsymbol{\mathrm{Cl}}}\:\mathrm{O}_{\mathrm{3}} \\ $$$$\left(\mathrm{b}\right)\underline{\mathrm{S}O}_{\mathrm{3}} ^{\mathrm{2}−} \\ $$$$\left(\mathrm{c}\right)\mathrm{H}_{\mathrm{2}} \underline{\mathrm{S}O}_{\mathrm{4}} \\ $$$$\left(\mathrm{d}\right)\underline{\mathrm{Na}}\:\mathrm{H} \\ $$$$ \\ $$
Commented by Tawa11 last updated on 08/Oct/22
(a)     1  +  x  −  6   =   0                 x   −   5   =   0                 x   =   5                  [Cl   =   5]    (b)     x   −   6    =    −  2                 x    =   −  2   +   6                 x   =   4                  [S   =   4]    (c)     2   +   x   −   8    =   0                 x   −   6   =   0                 x   =   6                  [S   =   6]    (d)       x   −   1   =   0                 x   =   1                  [Na   =   1]
$$\left(\mathrm{a}\right)\:\:\:\:\:\mathrm{1}\:\:+\:\:\mathrm{x}\:\:−\:\:\mathrm{6}\:\:\:=\:\:\:\mathrm{0} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{x}\:\:\:−\:\:\:\mathrm{5}\:\:\:=\:\:\:\mathrm{0} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{x}\:\:\:=\:\:\:\mathrm{5}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\left[\mathrm{Cl}\:\:\:=\:\:\:\mathrm{5}\right] \\ $$$$ \\ $$$$\left(\mathrm{b}\right)\:\:\:\:\:\mathrm{x}\:\:\:−\:\:\:\mathrm{6}\:\:\:\:=\:\:\:\:−\:\:\mathrm{2} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{x}\:\:\:\:=\:\:\:−\:\:\mathrm{2}\:\:\:+\:\:\:\mathrm{6} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{x}\:\:\:=\:\:\:\mathrm{4}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\left[\mathrm{S}\:\:\:=\:\:\:\mathrm{4}\right] \\ $$$$ \\ $$$$\left(\mathrm{c}\right)\:\:\:\:\:\mathrm{2}\:\:\:+\:\:\:\mathrm{x}\:\:\:−\:\:\:\mathrm{8}\:\:\:\:=\:\:\:\mathrm{0} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{x}\:\:\:−\:\:\:\mathrm{6}\:\:\:=\:\:\:\mathrm{0} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{x}\:\:\:=\:\:\:\mathrm{6}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\left[\mathrm{S}\:\:\:=\:\:\:\mathrm{6}\right] \\ $$$$ \\ $$$$\left(\mathrm{d}\right)\:\:\:\:\:\:\:\mathrm{x}\:\:\:−\:\:\:\mathrm{1}\:\:\:=\:\:\:\mathrm{0} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{x}\:\:\:=\:\:\:\mathrm{1}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\left[\mathrm{Na}\:\:\:=\:\:\:\mathrm{1}\right] \\ $$
Commented by Spillover last updated on 08/Oct/22
perfect.
$$\mathrm{perfect}. \\ $$

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