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find-the-product-of-roots-2021-1-3-x-log-2021-x-x-3-




Question Number 103047 by bemath last updated on 12/Jul/20
find the product of roots   ((2021))^(1/(3 ))  x^(log_(2021)  (x))  = x^3
findtheproductofroots20213xlog2021(x)=x3
Commented by mr W last updated on 12/Jul/20
Πx=2021^3  ?
Πx=20213?
Answered by floor(10²Eta[1]) last updated on 12/Jul/20
log_(2021) (x)=y⇒x=2021^y   ⇒((2021))^(1/3) .(2021^y )^y =(2021^y )^3   2021^(1/3) .2021^y^2  =2021^(3y)   ⇒y^2 +(1/3)=3y⇒y^2 −3y+(1/3)=0  product=x_1 .x_2 =2021^y_1  .2021^y_2    =2021^(y_1 +y_2 ) =2021^3
log2021(x)=yx=2021y20213.(2021y)y=(2021y)320211/3.2021y2=20213yy2+13=3yy23y+13=0product=x1.x2=2021y1.2021y2=2021y1+y2=20213
Answered by bemath last updated on 14/Jul/20
set x=2021^y  ⇔ y=log _(2021) (x)  ⇒2021^(1/3) (2021^y )^y  = 2021^(3y)   2021^(y^2 −3y+(1/3))  = 1   ⇒y^2 −3y+(1/3) = 0 ; Δ=9−(4/3)>0   ⇒(y−a)(y−b) = 0⇒a+b = 3  A=2021^a  ;B = 2021^b   ⇔A.B = 2021^(a+b)  = 2021^3   = 21^3  (mod 100) = 261 (mod  1000)
setx=2021yy=log2021(x)202113(2021y)y=20213y2021y23y+13=1y23y+13=0;Δ=943>0(ya)(yb)=0a+b=3A=2021a;B=2021bA.B=2021a+b=20213=213(mod100)=261(mod1000)

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