Question Number 185518 by Mastermind last updated on 23/Jan/23
$$\mathrm{Find}\:\mathrm{the}\:\mathrm{radius}\:\mathrm{of}\:\mathrm{convergence}\:\mathrm{of} \\ $$$$\underset{\mathrm{n}=\mathrm{1}} {\overset{\infty} {\sum}}\mathrm{ne}^{−\mathrm{n}^{\mathrm{2}} } \\ $$$$ \\ $$$$\mathrm{M}.\mathrm{m} \\ $$
Commented by aleks041103 last updated on 30/Apr/23
$${this}\:{series}\:{is}\:{independent}\:{of}\:{any}\:{additional} \\ $$$${parameters},\:{i}.{e}.\:{we}\:{cannot}\:{define}\:{radius} \\ $$$${of}\:{convergence} \\ $$