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find-the-range-of-f-x-1-2x-1-




Question Number 32489 by NECx last updated on 26/Mar/18
find the range of f(x)=1+(√(2x−1))
findtherangeoff(x)=1+2x1
Commented by prof Abdo imad last updated on 28/Mar/18
D_f =[(1/2),+∞[  and f^′ (x) =  (1/( (√(2x−1))))  >0 on](1/2),+∞[  lim_(x→+∞) f(x)=+∞  and   f([(1/2),+∞[ =[f((1/2)),^�  +∞[ =[1 ,+∞[  .
Df=[12,+[andf(x)=12x1>0on]12,+[limx+f(x)=+andf([12,+[=[f(12),¯+[=[1,+[.
Answered by MJS last updated on 26/Mar/18
domain: x∈R∧x≧(1/2)  range: x∈R∧x≧1
domain:xRx12range:xRx1

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