Menu Close

Find-the-range-of-f-x-3-2-x-2-




Question Number 16457 by Tinkutara last updated on 22/Jun/17
Find the range of f(x) = (3/(2 − x^2 ))
Findtherangeoff(x)=32x2
Answered by sandy_suhendra last updated on 22/Jun/17
y = (3/(2−x^2 ))  y(2−x^2 )=3  2y−x^2 y=3  x^2 y=2y−3  x^2 = ((2y−3)/y)  x = (√((2y−3)/y))  f^(−1) (x) = (√((2x−3)/x))  range of f(x) is domain of f^(−1) (x)  ((2x−3)/x) ≥ 0  ⇒  x < 0  or x ≥ 1(1/2)  range of f(x) = {y∣ y < 0  or y ≥ 1(1/2)}
y=32x2y(2x2)=32yx2y=3x2y=2y3x2=2y3yx=2y3yf1(x)=2x3xrangeoff(x)isdomainoff1(x)2x3x0x<0orx112rangeoff(x)={yy<0ory112}

Leave a Reply

Your email address will not be published. Required fields are marked *