find-the-roots-of-8x-3-4x-1-0- Tinku Tara June 4, 2023 Algebra 0 Comments FacebookTweetPin Question Number 39026 by maxmathsup by imad last updated on 01/Jul/18 findtherootsof8x3−4x−1=0 Answered by behi83417@gmail.com last updated on 02/Jul/18 x1=−128x3−4x−1=(2x+1)(4x2+ax+b)x=0⇒−1=(1)(b)⇒b=−1x=1⇒3=(3)(4+a−1)⇒a=−2⇒4x2−2x−1=0⇒x=2±4+168=14(1±5)⇒x=−12,14(1±5). Answered by tanmay.chaudhury50@gmail.com last updated on 02/Jul/18 8x3−4x−(2−1)=08x3−4x−2+1=08x3+1−2(2x+1)=0(2x+1)(4x2−2x.1+12)−2(2x+1)=0(2x+1)(4x2−2x+1−2)=0(2x+1)(4x2−2x−1)=0x=−124x2−2x−1=0x=2±4+168=2±258=1±54 Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: Question-170099Next Next post: 3-5-1-1-x-1-3-dx-1-3-5-1-1-x-1-3-dx- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.