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Question Number 84394 by jagoll last updated on 12/Mar/20
find the solution  ((2x)/(x−2)) ≤ ∣x−3∣
findthesolution2xx2x3
Commented by john santu last updated on 12/Mar/20
(i) x ≥3 ⇒ ((2x)/(x−2)) ≤ x−3  ⇒2x ≤ (x−3)(x−2)  ⇒2x ≤ x^2 −5x+6   ⇒x^2 −7x+6 ≥0 , (x−1)(x−6)≥0  {x≤ 1 ∨ x ≥ 6 } ∧ x ≥ 3  •) x ≥ 6  (ii) x < 3 ⇒((2x)/(x−2)) ≤ 3−x  ⇒ ((2x−(3−x)(x−2))/(x−2)) ≤ 0  ((2x−(−x^2 +5x−6))/(x−2)) ≤ 0  ((x^2 −3x+6)/(x−2)) ≤ 0 ⇒•) x < 2   the solution (−∞, 2) ∨ [ 6, ∞)
(i)x32xx2x32x(x3)(x2)2xx25x+6x27x+60,(x1)(x6)0{x1x6}x3)x6(ii)x<32xx23x2x(3x)(x2)x202x(x2+5x6)x20x23x+6x20)x<2thesolution(,2)[6,)
Commented by jagoll last updated on 12/Mar/20
thank you sir
thankyousir

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