find-the-square-root-of-7x-2-2-14-x-2-x-2-1-2-x-1-6-

Question Number 171869 by Mikenice last updated on 21/Jun/22

f i n d t h e s q u a r e r o o t o f :

\sqrt{\frac{7 x^{2} + 2 \sqrt{14} x + 2}{x^{2} - \frac{1}{2} x + \frac{1}{6}}}

Answered by floor(10²Eta[1]) last updated on 21/Jun/22

found it, {it}^{'} s right above my answer

Commented by Mikenice last updated on 21/Jun/22

o k a y s i r, s h o w t h e s o l u t i o n s i r

Commented by floor(10²Eta[1]) last updated on 21/Jun/22

what solution ? ? ? ? do you want that

expression a simplest form ? ?

Commented by Mikenice last updated on 21/Jun/22

y e s

Answered by floor(10²Eta[1]) last updated on 21/Jun/22

{7 x}^{2} + 2 \sqrt{14} x + 2 = {(\sqrt{7} x + \sqrt{2})}^{2}

x^{2} - \frac{1}{2} x + \frac{1}{6} = {(x - \frac{1}{4})}^{2} - \frac{1}{16} + \frac{1}{6} = {(x - \frac{1}{4})}^{2} + \frac{5}{48}

\sqrt{\frac{{7 x}^{2} + 2 \sqrt{14} x + 2}{x^{2} - \frac{1}{2} x + \frac{1}{6}}} = \frac{∣ \sqrt{7} x + \sqrt{2} ∣}{\sqrt{{(x - \frac{1}{4})}^{2} + \frac{5}{48}}}

Commented by mr W last updated on 21/Jun/22

m a y b e h e m e a n t a c t u a l l y

\sqrt{\frac{{7 x}^{2} + 2 \sqrt{14} x + 2}{x^{2} - \frac{1}{2} x + \frac{1}{16}}} .

o t h e r w i s e {i t}^{'} s a n o n - s e n s e q u e s t i o n!

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