Find-the-sum-of-the-all-positive-integers-of-all-positive-factorsof-12-

Question Number 124332 by ZiYangLee last updated on 02/Dec/20

Find the sum of the all positive integers

of all positive factorsof 12

Answered by mr W last updated on 02/Dec/20

12 = 2^{2} \times 3

n u m b e r o f f a c t o r s = (2 + 1) (1 + 1) = 6

f a c t o r s : 1, 2, 3, 4, 6, 12

s u m = 1 + 2 + 3 + 4 + 6 + 12 = 28

o r u s i n g f o r m u l a

s u m = \frac{2^{2 + 1} - 1}{2 - 1} \times \frac{3^{1 + 1} - 1}{3 - 1} = 7 \times 4 = 28

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