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Question Number 86088 by Serlea last updated on 27/Mar/20
Find the sum of the series below:  1+2+3−4−5−6+7+8+9−10−11−12+13+14+15...−3020
Findthesumoftheseriesbelow:1+2+3456+7+8+9101112+13+14+153020
Commented by Kunal12588 last updated on 27/Mar/20
did yoy forgot 10?  I think series should be like  1+2+3−4−5−6+7+8+9−10−11−12+13+...+3020
didyoyforgot10?Ithinkseriesshouldbelike1+2+3456+7+8+9101112+13++3020
Commented by Serlea last updated on 27/Mar/20
Merci
Merci
Commented by Prithwish Sen 1 last updated on 27/Mar/20
I think rhe question is   1+2+3−4−5−6+7+8+9−10−11−12......  −3016−3017−3018  =(1−4)+(2−5)+(3−6)+......(3013−3016)  +(3014−3017)+(3015−3018)  =(−3)×1509 = −4527  please check.
Ithinkrhequestionis1+2+3456+7+8+9101112301630173018=(14)+(25)+(36)+(30133016)+(30143017)+(30153018)=(3)×1509=4527pleasecheck.
Commented by Kunal12588 last updated on 28/Mar/20
see sir next term would be  ...+(3−6)+(4−7)+(5−8)+...  and these terms are not needed
seesirnexttermwouldbe+(36)+(47)+(58)+andthesetermsarenotneeded
Commented by Prithwish Sen 1 last updated on 28/Mar/20
I think you are making a mistake ,  actually it is  (1−4)+(2−5)+(3−6)+(7−10)+(8−11)+  (9−12)+(13−16)+(14−17)+(15−18)+..  amd so on.  look here nothing is repeated. You have to   take six numbers as a group like  1+2+3−4−5−6    then  7+8+9−10−11−12  then  13+14+15−16−17−18  and so on.
Ithinkyouaremakingamistake,actuallyitis(14)+(25)+(36)+(710)+(811)+(912)+(1316)+(1417)+(1518)+..amdsoon.lookherenothingisrepeated.Youhavetotakesixnumbersasagrouplike1+2+3456then7+8+9101112then13+14+15161718andsoon.

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