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find-the-value-of-0-dx-2x-1-2x-3-




Question Number 32360 by prof Abdo imad last updated on 23/Mar/18
find the value of  ∫_0 ^∞     (dx/((2x+1)(2x+3))) .
findthevalueof0dx(2x+1)(2x+3).
Commented by abdo imad last updated on 25/Mar/18
I = ∫_0 ^∞     (dx/((2x+1)(2x+3))) =(1/2) ∫_0 ^∞  ( (1/(2x+1)) −(1/(2x+3)))dx  (1/4) ∫_0 ^∞  ( (2/(2x+1)) −(2/(2x+3)))dx=(1/4)[ln∣((2x+1)/(2x+3))∣]_0 ^∞   I =−(1/4)ln((1/3)) =(1/4)ln(3) .
I=0dx(2x+1)(2x+3)=120(12x+112x+3)dx140(22x+122x+3)dx=14[ln2x+12x+3]0I=14ln(13)=14ln(3).

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