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find-the-value-of-D-dxdy-4x-2-y-2-1-2-D-x-y-R-2-x-2-y-2-1-and-y-2x-




Question Number 32342 by abdo imad last updated on 23/Mar/18
find the value of ∫∫_D    ((dxdy)/((4x^2  +y^2 +1)^2 ))  D={(x,y)∈ R^2  / x^2  +y^2  ≤1 and y ≤2x } .
$${find}\:{the}\:{value}\:{of}\:\int\int_{{D}} \:\:\:\frac{{dxdy}}{\left(\mathrm{4}{x}^{\mathrm{2}} \:+{y}^{\mathrm{2}} +\mathrm{1}\right)^{\mathrm{2}} } \\ $$$${D}=\left\{\left({x},{y}\right)\in\:{R}^{\mathrm{2}} \:/\:{x}^{\mathrm{2}} \:+{y}^{\mathrm{2}} \:\leqslant\mathrm{1}\:{and}\:{y}\:\leqslant\mathrm{2}{x}\:\right\}\:. \\ $$

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