Find-the-value-of-x-satisfying-sin-2-x-sin-x-2-0-

Question Number 14879 by Tinkutara last updated on 05/Jun/17

Find the value of x, satisfying

\sin^{2} x + \sin x - 2 ⩾ 0

Answered by ajfour last updated on 05/Jun/17

{(\sin x + \frac{1}{2})}^{2} = 2 + \frac{1}{4} = {(\frac{3}{2})}^{2}

\Rightarrow \sin x = 1 (a s \sin x \neq - 2

x = 2 n π + \frac{π}{2} \Leftrightarrow x = n π + {(- 1)}^{n} \frac{π}{2} .

Commented by Tinkutara last updated on 05/Jun/17

Thanks Sir!