Find-the-volume-of-the-solid-obtained-by-rotating-about-x-axis-of-the-curve-y-x-on-the-interval-0-2-Mastermind-

Question Number 170996 by Mastermind last updated on 06/Jun/22

F i n d t h e v o l u m e o f t h e s o l i d o b t a i n e d

b y r o t a t i n g a b o u t x - a x i s o f t h e c u r v e

y = \sqrt{x} o n t h e i n t e r v a l [0, 2] .

M a s t e r m i n d

Answered by mr W last updated on 06/Jun/22

M e t h o d I :

V = 2 π \times \frac{2 \times 2 \times \sqrt{2}}{3} \times \frac{3 \sqrt{2}}{8} = 2 π

M e t h o d I I :

V = π \int_{0}^{2} y^{2} d x = π \int_{0}^{2} x d x = \frac{π}{2} (2^{2} - 0^{2}) = 2 π

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