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find-values-a-b-c-such-that-1-ax-2-bx-c-1-and-6b-2-8-a-2-3-is-Max-




Question Number 146062 by mnjuly1970 last updated on 10/Jul/21
      find  values  a , b , c  such that:      −1≤ ax^2 +bx +c ≤ 1        and  ((6b^( 2) + 8 a^( 2) )/3) is Max...
findvaluesa,b,csuchthat:1ax2+bx+c1and6b2+8a23isMax
Commented by mr W last updated on 10/Jul/21
it′s not possible with a≠0 and b≠0  that  −1≤ ax^2 +bx +c ≤ 1.  that means, such that  −1≤ ax^2 +bx +c ≤ 1  we must have a=b=0.  −1≤c≤1.  since max=((6b^2 +8a^2 )/3) =0 ⇒c=0
itsnotpossiblewitha0andb0that1ax2+bx+c1.thatmeans,suchthat1ax2+bx+c1wemusthavea=b=0.1c1.sincemax=6b2+8a23=0c=0

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