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find-x-1-3-x-dx-




Question Number 45231 by maxmathsup by imad last updated on 10/Oct/18
find ∫ (√((x−1)(3−x)))dx
find(x1)(3x)dx
Commented by maxmathsup by imad last updated on 12/Oct/18
let A =∫ (√((x−1)(3−x)))dx ⇒A =∫(√(3x−x^2 −3+x))dx=∫(√(−x^2  +4x−3))dx  =∫(√(−(x^2 −4x +4−4)−3))dx=∫(√(1−(x−2)^2 ))dxchangement  x−2=sint give A =∫  costcost dt =∫ ((1+cos(2t))/2)dt  =(t/2) +(1/4)sin(2t)+c =(t/2) +(1/2)sin(t)cos(t) +c  =(1/2) arcsin(x−2) +((x−2)/2)(√(1−(x−2)^2 ))+c
letA=(x1)(3x)dxA=3xx23+xdx=x2+4x3dx=(x24x+44)3dx=1(x2)2dxchangementx2=sintgiveA=costcostdt=1+cos(2t)2dt=t2+14sin(2t)+c=t2+12sin(t)cos(t)+c=12arcsin(x2)+x221(x2)2+c
Answered by tanmay.chaudhury50@gmail.com last updated on 11/Oct/18
∫(√(3x−x^2 −3+x dx))  ∫(√(−3+4x−x^2 )) dx  ∫(√(−3+4−4+4x−x^2 )) dx  ∫(√(1−(x−2)^2 )) dx  use formula ∫(√(a^2 −x^2 )) dx  ((x−2)/2)(√(1−(x−2)^2 )) +(1/2)sin^(−1) (((x−2)/1))+c
3xx23+xdx3+4xx2dx3+44+4xx2dx1(x2)2dxuseformulaa2x2dxx221(x2)2+12sin1(x21)+c
Answered by ajfour last updated on 11/Oct/18
let  x−2 = t  ∫(√((x−1)(3−x)))dx = ∫(√((t+1)(1−t)))dt    = ∫(√(1−t^2 )) dt    = (t/2)(√(1−t^2 ))+(1/2)sin^(−1) t +c   = (((x−2)/2))(√((x−1)(3−x)))+(1/2)sin^(−1) (x−2)+c .
letx2=t(x1)(3x)dx=(t+1)(1t)dt=1t2dt=t21t2+12sin1t+c=(x22)(x1)(3x)+12sin1(x2)+c.
Commented by Necxx last updated on 12/Oct/18
hmmm....I caught it.Thanks
hmmm.Icaughtit.Thanks

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