Question Number 42019 by Tawa1 last updated on 16/Aug/18

Commented by math khazana by abdo last updated on 17/Aug/18
![let f(x)=2^x +3^x −13 (e)⇔ f(x)=0 f(x)=e^(xln(2)) +e^(xln3) −13 ⇒ f^′ (x) =ln(2) 2^x +ln(3)3^x >0 so f is increasing on R we have lim_(x →−∞) f(x)=−13 and lim_(x→+∞) f(x)=+∞ so ∃ x_0 ∈R /f(x_0 )=0 we have f(0) =−13 <0 and f(3)=2^3 +3^3 −13 =8 +27−13 =22>0 ⇒ x_0 ∈]0,3[ we can verify that x_0 =2 is exact solution to f(x)=0](https://www.tinkutara.com/question/Q42026.png)
Commented by Tawa1 last updated on 17/Aug/18

Commented by maxmathsup by imad last updated on 17/Aug/18

Answered by MJS last updated on 17/Aug/18

Commented by Tawa1 last updated on 17/Aug/18

Commented by MJS last updated on 17/Aug/18

Commented by Tawa1 last updated on 17/Aug/18
