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Find-x-5-x-3-1-dx-Answer-I-2-45-3x-3-2-x-3-1-3-c-




Question Number 179175 by Acem last updated on 26/Oct/22
 Find ∫x^5  (√(x^3 +1)) dx      Answer: I= (2/(45)) (3x^3 −2) (√((x^3 +1)^3 )) + c
Findx5x3+1dxAnswer:I=245(3x32)(x3+1)3+c
Commented by Acem last updated on 26/Oct/22
 Wonderful Sir!
WonderfulSir!
Commented by cortano1 last updated on 26/Oct/22
 I=∫ x^3  (x^2  (√(x^3 +1)) )dx   let (√(x^3 +1)) = h⇒x^3 =h^2 −1    x^2  dx =(2/3)h dh    I=(2/3)∫(h^2 −1)h^2  dh =(2/3)∫ (h^4 −h^2 )dh    =(2/3)((1/5)h^5 −(1/3)h^3 )+c    =(2/3)h^3 ((1/5)h^2 −(1/3))+c    =(2/3)(√((x^3 +1)^3 )) ((1/5)(x^3 +1)−(1/3))+c    =(2/3)(√((x^3 +1)^3 )) (((3x^3 −2)/(15)))+c    = (2/(45)) (√((x^3 +1)^3 )) (3x^3 −2)+c
I=x3(x2x3+1)dxletx3+1=hx3=h21x2dx=23hdhI=23(h21)h2dh=23(h4h2)dh=23(15h513h3)+c=23h3(15h213)+c=23(x3+1)3(15(x3+1)13)+c=23(x3+1)3(3x3215)+c=245(x3+1)3(3x32)+c

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