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find-y-if-y-3-y-1-lt-2-i-mean-modulus-by-




Question Number 33837 by NECx last updated on 25/Apr/18
find y if ∣((y−3)/(y+1))∣<2    i mean modulus by ∣
findyify3y+1∣<2imeanmodulusby
Answered by Rasheed.Sindhi last updated on 26/Apr/18
find y if ∣((y−3)/(y+1))∣<2       ±((y−3)/(y+1))<2        ±(y−3)<2(y+1) ∧ y+1>0.......A                                          or        ±(y−3)>2(y+1) ∧ y+1<0.......B  A           y−3<2y+2  ∧ y>−1............A1            y>−5 ∧ y>−1           y>−1   or           −y+3<2y+2 ∧ y>−1..........A2            3y>1∧ y>−1            y>1/3  ∧   y>−1            y>1/3    A:         A1 or A2 :   y>−1 ∨ y>1/3                            y>−1  −−−−−−−−−  B            y−3>2y+2 ∧ y<−1....B1             y<−5 ∧ y<−1             y<−5              or         −y+3>2y+2 ∧ y<−1....B2            y<1/3  ∧ y<−1           y<−1  B:    B1 or  B2: y<−5 ∨ y<−1                                y<−1  −−−−−−−−−  Ans : A or B:  y>−1 or y<−1                           Some error is there.
findyify3y+1∣<2±y3y+1<2±(y3)<2(y+1)y+1>0.Aor±(y3)>2(y+1)y+1<0.BAy3<2y+2y>1A1y>5y>1y>1ory+3<2y+2y>1.A23y>1y>1y>1/3y>1y>1/3A:A1orA2:y>1y>1/3y>1By3>2y+2y<1.B1y<5y<1y<5ory+3>2y+2y<1.B2y<1/3y<1y<1B:B1orB2:y<5y<1y<1Ans:AorB:y>1ory<1Someerroristhere.
Commented by MJS last updated on 26/Apr/18
−2<((y−3)/(y+1))<2 ⇒ −2<((y−3)/(y+1)) ∧ ((y−3)/(y+1))<2  y+1≠0 ⇒ y≠−1    1. y+1<0 ⇒ y<−1  −2(y+1)>y−3 ∧ y−3>2(y+1)  y<(1/3) ∧ y<−5 ⇒ y<−5    2. y+1>0 ⇒ y>−1  −2(y+1)<y−3 ∧ y−3<2(y+1)  y>(1/3) ∧ y>−5 ⇒ y>(1/3)    y<−5 ∨ y>(1/3)  y∈ ]−∞; −5[ ∪ ](1/3); ∞[  ...but anyway he meant mod(((y−3)/(y+1)))<2
2<y3y+1<22<y3y+1y3y+1<2y+10y11.y+1<0y<12(y+1)>y3y3>2(y+1)y<13y<5y<52.y+1>0y>12(y+1)<y3y3<2(y+1)y>13y>5y>13y<5y>13y];5[]13;[butanywayhemeantmod(y3y+1)<2
Answered by MJS last updated on 26/Apr/18
mod(5/3)=2 because 1×3+2=5  which definition shall we use for mod(−5/3) and  mod(5/−3)?
mod(5/3)=2because1×3+2=5whichdefinitionshallweuseformod(5/3)andmod(5/3)?

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