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fnd-xe-x-2-arctan-1-1-x-dx-

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Question Number 83246 by mathmax by abdo last updated on 29/Feb/20
fnd ∫ xe^(−x^2 ) arctan(1−(1/x))dx
$${fnd}\:\int\:{xe}^{−{x}^{\mathrm{2}} } {arctan}\left(\mathrm{1}−\frac{\mathrm{1}}{{x}}\right){dx} \\ $$

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