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For-a-certain-amount-of-work-Ade-takes-6hours-less-than-Bode-if-they-work-together-it-takes-them-13hours-20-minutes-How-long-will-it-take-Bode-alone-to-complete-the-work-




Question Number 25937 by Mr eaay last updated on 16/Dec/17
For a certain amount of work,Ade takes  6hours less than Bode.if they work together  it takes them 13hours 20 minutes.How  long will it take Bode alone to complete  the work?
Foracertainamountofwork,Adetakes6hourslessthanBode.iftheyworktogetherittakesthem13hours20minutes.HowlongwillittakeBodealonetocompletethework?
Answered by ajfour last updated on 16/Dec/17
800(A+B) minutes =W  T_B −T_A =360 minutes  as  W=T_A A=T_B B  ⇒ (W/B)−(W/A)= 360  so  (W/B)−(W/(((W/(800))−B)))=360  as    T_B =(W/B)  ⇒   T_B −(1/(((1/(800))−(1/T_B ))))=360  (1/(T_B −360)) =(1/(800))−(1/T_B )  ⇒   800T_B =(T_B −800)(T_B −360)  or   T_B ^(  2) −1960T_B +800×360=0 , ⇒  (T_B −980)^2 =980×980−800×360  T_B =980+20(√(49×49−720))       =980+20(√(2401−720))       =980+20(√(1681))      =980+20×41 =1800 minutes      = 30 hours  (Bode alone takes).
800(A+B)minutes=WTBTA=360minutesasW=TAA=TBBWBWA=360soWBW(W800B)=360asTB=WBTB1(18001TB)=3601TB360=18001TB800TB=(TB800)(TB360)orTB21960TB+800×360=0,(TB980)2=980×980800×360TB=980+2049×49720=980+202401720=980+201681=980+20×41=1800minutes=30hours(Bodealonetakes).

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