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For-a-reversible-reaction-A-B-Find-K-eq-at-2727-C-temperature-Given-r-H-30-kJ-mol-1-at-2727-C-r-S-10-JK-1-at-2727-C-R-8-314-JK-1-mol-1-




Question Number 24436 by Tinkutara last updated on 17/Nov/17
For a reversible reaction A ⇌ B. Find  K_(eq)  at 2727°C temperature.  Given : Δ_r H° = −30 kJ mol^(−1)  (at 2727°C)  Δ_r S° = 10 JK^(−1)  (at 2727°C)  R = 8.314 JK^(−1)  mol^(−1)
$$\mathrm{For}\:\mathrm{a}\:\mathrm{reversible}\:\mathrm{reaction}\:\mathrm{A}\:\rightleftharpoons\:\mathrm{B}.\:\mathrm{Find} \\ $$$$\mathrm{K}_{\mathrm{eq}} \:\mathrm{at}\:\mathrm{2727}°\mathrm{C}\:\mathrm{temperature}. \\ $$$$\mathrm{Given}\::\:\Delta_{\mathrm{r}} \mathrm{H}°\:=\:−\mathrm{30}\:\mathrm{kJ}\:\mathrm{mol}^{−\mathrm{1}} \:\left(\mathrm{at}\:\mathrm{2727}°\mathrm{C}\right) \\ $$$$\Delta_{\mathrm{r}} \mathrm{S}°\:=\:\mathrm{10}\:\mathrm{JK}^{−\mathrm{1}} \:\left(\mathrm{at}\:\mathrm{2727}°\mathrm{C}\right) \\ $$$$\mathrm{R}\:=\:\mathrm{8}.\mathrm{314}\:\mathrm{JK}^{−\mathrm{1}} \:\mathrm{mol}^{−\mathrm{1}} \\ $$

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