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For-any-real-numbers-x-y-and-z-if-x-y-z-2-then-prove-that-xyz-8-1-x-1-y-1-z-

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Question Number 112796 by nimnim last updated on 09/Sep/20
For any real numbers x,y and z if x+y+z=2, then prove that xyz≥8(1−x)(1−y)(1−z).
Foranyrealnumbersx,yandzifx+y+z=2,thenprovethatxyz⩾8(1−x)(1−y)(1−z).
Commented by nimnim last updated on 10/Sep/20
Yes sir..
Yessir..
Commented by 1549442205PVT last updated on 10/Sep/20
The inequality is false when x=−1.4 y=0.9,z=2.5 because xyz=−3.15 8(1−x)(1−y)(1−z)=−72/25=−2.88>−3.15 You need must look at your question It seems posted ago and was warned
Theinequalityisfalsewhenx=−1.4y=0.9,z=2.5becausexyz=−3.158(1−x)(1−y)(1−z)=−72/25=−2.88>−3.15YouneedmustlookatyourquestionItseemspostedagoandwaswarned

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