Question Number 30487 by abdo imad last updated on 22/Feb/18
$${for}\:{n}\geqslant\mathrm{2}\:{let}\:\:{x}_{{n}} =\:\:\frac{\sum_{{k}=\mathrm{1}} ^{{n}} \:\left[{lnk}\right]}{{ln}\left({n}!\right)}\:\:{find}\:{lim}_{{n}\rightarrow\infty} {x}_{{n}} \:\:. \\ $$