Question Number 27958 by bmind4860 last updated on 17/Jan/18

Answered by ajfour last updated on 17/Jan/18
![sin y ≥ sin x−cos αcos x ⇒ ≥ (√(1+cos^2 α)) [(1/( (√(1+cos^2 α))))sin x−((cos α)/( (√(1+cos^2 α))))cos x] sin y≥ (√(1+cos^2 α)) sin [x−tan^(−1) (cos α)] since x can be any value, and sin y ≤ 1 ⇒ cos α=0 ⇒ sin α =±1 then this implies sin y ≥ sin x and again for this to be always true sin y =1 hence sin y+sin α=0 or 2 .](https://www.tinkutara.com/question/Q27962.png)
Commented by bmind4860 last updated on 17/Jan/18

Commented by ajfour last updated on 17/Jan/18

Commented by bmind4860 last updated on 17/Jan/18
