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From-1-to-50-1-and-50-includes-fev-n-for-n-2-1-n-n-full-number-




Question Number 127414 by MathSh last updated on 29/Dec/20
From 1 to 50 (1 and 50 includes)  fev n for (((n^2 −1)!)/((n!)^n )) full number
$${From}\:\mathrm{1}\:{to}\:\mathrm{50}\:\left(\mathrm{1}\:{and}\:\mathrm{50}\:{includes}\right) \\ $$$${fev}\:{n}\:{for}\:\frac{\left({n}^{\mathrm{2}} −\mathrm{1}\right)!}{\left({n}!\right)^{{n}} }\:{full}\:{number} \\ $$
Commented by talminator2856791 last updated on 29/Dec/20
 what is fev?
$$\:\mathrm{what}\:\mathrm{is}\:\mathrm{fev}? \\ $$
Commented by MathSh last updated on 29/Dec/20
From 1 to 50 how many n numbers  which is (((n^2 −1))/((n!)^n )) is integer..
$${From}\:\mathrm{1}\:{to}\:\mathrm{50}\:{how}\:{many}\:{n}\:{numbers} \\ $$$${which}\:{is}\:\frac{\left({n}^{\mathrm{2}} −\mathrm{1}\right)}{\left({n}!\right)^{{n}} }\:{is}\:{integer}.. \\ $$
Commented by talminator2856791 last updated on 29/Dec/20
 oooooohhhhhhh
$$\:\mathrm{oooooohhhhhhh} \\ $$
Commented by MathSh last updated on 29/Dec/20
Sorry sir, solution please..
$${Sorry}\:{sir},\:{solution}\:{please}.. \\ $$
Answered by talminator2856791 last updated on 08/Sep/21
    n^2 −1 = (n+1)(n−1)   ⇒ prime n+1 dont satisfy conditions.    ⇒ 50− # primes ≤ 50         50−15    = 35
$$\: \\ $$$$\:{n}^{\mathrm{2}} −\mathrm{1}\:=\:\left({n}+\mathrm{1}\right)\left({n}−\mathrm{1}\right) \\ $$$$\:\Rightarrow\:\mathrm{prime}\:{n}+\mathrm{1}\:\mathrm{dont}\:\mathrm{satisfy}\:\mathrm{conditions}.\: \\ $$$$\:\Rightarrow\:\mathrm{50}−\:#\:\mathrm{primes}\:\leqslant\:\mathrm{50} \\ $$$$\:\:\:\:\:\:\:\mathrm{50}−\mathrm{15} \\ $$$$\:\:=\:\mathrm{35} \\ $$$$\: \\ $$

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