From-the-standard-equation-of-a-circle-using-the-origin-0-0-we-deduced-the-eqution-x-a-2-y-b-2-r-2-to-x-2-y-2-r-2-In-what-terms-do-we-use-this-formular-

Question Number 166641 by pete last updated on 23/Feb/22

From the standard equation of a circle,

using the origin (0, 0), we deduced the eqution

{(x - a)}^{2} + {(y - b)}^{2} = r^{2} to x^{2} + y^{2} = r^{2} .

In what terms do we use this formular ?

Commented by MJS_new last updated on 24/Feb/22

well, we use this formula every time we have

a circle with center (0 ∣ 0) and radius r \dots

the question seems strange to me .

Answered by alephzero last updated on 24/Feb/22

{(x - a)}^{2} + {(y - b)}^{2} = r^{2}

\Rightarrow {(y - b)}^{2} = r^{2} - {(x - a)}^{2}

\Rightarrow y - b = \pm \sqrt{r^{2} - {(x - a)}^{2}}

\Rightarrow y = \pm \sqrt{r^{2} - {(x - a)}^{2}} - b

Plot of this equation looks like a

circle .

Commented by mr W last updated on 24/Feb/22

f o r m e {(x - a)}^{2} + {(y - b)}^{2} = r^{2} l o o k s

m o r e l i k e a c i r c l e t h a n

y = \pm \sqrt{r^{2} - {(x - a)}^{2}} - b .

Commented by pete last updated on 24/Feb/22

Thanks Sir

Facebook Tweet Pin