Menu Close

g-n-g-n-1-g-n-2-g-1-1-g-2-3-g-n-




Question Number 31991 by gunawan last updated on 17/Mar/18
g_n =(√(g_(n−1) +g_(n−2) ))  g_1 =1  g_2 =3  g_n =..
$${g}_{{n}} =\sqrt{{g}_{{n}−\mathrm{1}} +{g}_{{n}−\mathrm{2}} } \\ $$$${g}_{\mathrm{1}} =\mathrm{1} \\ $$$${g}_{\mathrm{2}} =\mathrm{3} \\ $$$${g}_{{n}} =.. \\ $$
Commented by mondodotto@gmail.com last updated on 18/Mar/18
g_n =(√(g_(n−1) +g_(n−2) ))
$$\boldsymbol{{g}}_{\boldsymbol{{n}}} =\sqrt{\boldsymbol{{g}}_{\boldsymbol{{n}}−\mathrm{1}} +\boldsymbol{{g}}_{\boldsymbol{{n}}−\mathrm{2}} } \\ $$

Leave a Reply

Your email address will not be published. Required fields are marked *