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Question Number 145938 by Mathspace last updated on 09/Jul/21
g(x)=cos(arctanx)  if g(x)=Σ a_n x^n  determine the  sequence a_n
g(x)=cos(arctanx)ifg(x)=Σanxndeterminethesequencean
Answered by Olaf_Thorendsen last updated on 09/Jul/21
If x∈R, artanx ∈]−(π/2),+(π/2)[  ⇒ cos(arctanx) > 0  cos(arctanx) = +(√(cos^2 (arctanx)))  cos(arctanx) = (√((cos^2 (arctanx))/(cos^2 (actanx)+sin^2 (arctanx))))  cos(arctanx) = (1/( (√(1+tan^2 (arctanx))))) = (1/( (√(1+x^2 ))))  a_(2n)  = (−1)^n ((1.3.5...(2n−1))/(2.4.6...(2n)))  a_(2n)  = (−1)^n (((2n)!)/(2^(2n) n!^2 ))  and a_(2n+1)  = 0
IfxR,artanx]π2,+π2[cos(arctanx)>0cos(arctanx)=+cos2(arctanx)cos(arctanx)=cos2(arctanx)cos2(actanx)+sin2(arctanx)cos(arctanx)=11+tan2(arctanx)=11+x2a2n=(1)n1.3.5(2n1)2.4.6(2n)a2n=(1)n(2n)!22nn!2anda2n+1=0

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