geometric-series-b-4-b-7-b-10-b-1-b-3-b-5-2-12-find-b-5-b-2- Tinku Tara June 4, 2023 Algebra 0 Comments FacebookTweetPin Question Number 149424 by mathdanisur last updated on 05/Aug/21 geometricseriesb4⋅b7⋅b10b1⋅b3⋅b5=212findb5b2=? Answered by nimnim last updated on 05/Aug/21 bn=arn−1,thenwehavear3.ar6.ar9a.ar2.ar4=212⇒r12=212⇒r=2∴b5b2=ar4ar=r3=23=8★ Commented by mathdanisur last updated on 05/Aug/21 ThankyouSer Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: To-the-developers-of-TinkuTara-problem-1-i-get-no-notifications-when-my-posts-are-updated-problem-2-i-can-edit-my-post-see-picture-1-but-the-content-is-not-visiable-see-picture-2-Next Next post: Question-149425 Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.