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geometric-series-b-4-b-7-b-10-b-1-b-3-b-5-2-12-find-b-5-b-2-




Question Number 149424 by mathdanisur last updated on 05/Aug/21
geometric series  ((b_4 ∙b_7 ∙b_(10) )/(b_1 ∙b_3 ∙b_5 )) = 2^(12)   find   (b_5 /b_2 ) = ?
geometricseriesb4b7b10b1b3b5=212findb5b2=?
Answered by nimnim last updated on 05/Aug/21
   b_n =ar^(n−1) , then we have             ((ar^3 .ar^6 .ar^9 )/(a.ar^2 .ar^4 ))=2^(12)    ⇒  r^(12) =2^(12) ⇒r=2    ∴ (b_5 /b_2 )=((ar^4 )/(ar))=r^3 =2^3 =8 ★
bn=arn1,thenwehavear3.ar6.ar9a.ar2.ar4=212r12=212r=2b5b2=ar4ar=r3=23=8
Commented by mathdanisur last updated on 05/Aug/21
Thank you Ser
ThankyouSer

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