Given-a-b-0-4-309a-15c-226b-1-show-that-2b-0-3-and-3a-1-5- Tinku Tara June 4, 2023 Vector Calculus 0 Comments FacebookTweetPin Question Number 122358 by mathocean1 last updated on 16/Nov/20 Givena,b∈[0;4]309a+15c=226b1)showthat2b≡0[3]and3a≡1[5] Answered by mindispower last updated on 16/Nov/20 309a+15c=226b=225b+b309a+15c=3(103a+5c)≡0[3]⇒3(75b)+b≡0[3]⇔b≡0[3]⇒2b=0.2[3]≡0[3]309a=226b−15c≡b[5]309=4+5.61⇔4a≡b[5]⇒−a=b[5]⇒a=−b[5]⇒3a=2b[5]2b=3kfirstresult,⇒2b∈{0,6}b=0⇒309.0+15.0=0,{0,0,0}solution3a≠1[5]b≠0⇒2b=6≡1[5]3a=2b[5]⇔3a=1[5],wemusteb∈[1,4] Commented by mathocean1 last updated on 18/Nov/20 thankssir Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: Question-56823Next Next post: Question-56824 Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.
![Given a, b ∈[0;4] 309a+15c=226b 1) show that 2b≡0[3] and 3a≡1[5]](https://www.tinkutara.com/question/Q122358.png)
![309a+15c=226b=225b+b 309a+15c=3(103a+5c)≡0[3] ⇒3(75b)+b≡0[3]⇔b≡0[3]⇒2b=0.2[3]≡0[3] 309a=226b−15c≡b[5] 309=4+5.61 ⇔4a≡b[5]⇒−a=b[5]⇒a=−b[5] ⇒3a=2b[5] 2b=3k first result,⇒2b∈{0,6} b=0⇒309.0+15.0=0,{0,0,0} solution 3a≠1[5] b≠0⇒2b=6≡1[5] 3a=2b[5]⇔3a=1[5],we muste b∈[1,4]](https://www.tinkutara.com/question/Q122374.png)
