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Given-a-function-f-x-2ax-2-x-3-1-3-Find-the-inclined-asymptotes-




Question Number 125099 by bramlexs22 last updated on 08/Dec/20
 Given a function f(x) = ((2ax^2 −x^3 ))^(1/3) .  Find the inclined asymptotes
Givenafunctionf(x)=2ax2x33.Findtheinclinedasymptotes
Answered by liberty last updated on 08/Dec/20
 k = lim_(x→±∞)  (y/x) = lim_(x→±∞) (((2ax^2 −x^3 ))^(1/3) /x)       lim_(x→±∞)  ((((2a)/x)−1))^(1/3)  = −1   b =lim_(x→±∞)  [y−kx ] = lim_(x→±∞) [ ((2ax^2 −x^3  ))^(1/3)  + x ]    = lim_(x→±∞)  ((2ax^2 −x^3 +x^3 )/( (((2ax^2 −x^3 )^2 ))^(1/3) −x ((2ax^2 −x^3 ))^(1/3)  +x^2 ))    = lim_(x→±∞) ((2ax^2 )/( (((2ax^2 −x^3 )^2 ))^(1/3) −x ((2ax^2 −x^3 ))^(1/3) +x^2 )) = ((2a)/3)  thus the straight line y=−x+((2a)/3) is a inclined  asymptotes to the curve y =((2ax^2 −x^3 ))^(1/3)  .
k=limx±yx=limx±2ax2x33xlimx±2ax13=1b=limx±[ykx]=limx±[2ax2x33+x]=limx±2ax2x3+x3(2ax2x3)23x2ax2x33+x2=limx±2ax2(2ax2x3)23x2ax2x33+x2=2a3thusthestraightliney=x+2a3isainclinedasymptotestothecurvey=2ax2x33.
Commented by bramlexs22 last updated on 08/Dec/20
thanks a lot
thanksalot

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