Given-a-function-H-x-sin-x-cos-x-2-cos-x-with-x-0-2pi-find-H-x-max-and-H-x-min-

Question Number 94125 by i jagooll last updated on 17/May/20

Given a function

H (x) = ∣ \sin x + \cos x ∣ + \sqrt{2} \cos x

with x \in [0, 2 π]

find H {(x)}_{\max} and H {(x)}_{\min}

Answered by john santu last updated on 17/May/20

H {(x)}_{\max} = \sqrt{4 + 2 \sqrt{2}}, when x = \frac{3 π}{8}

H {(x)}_{\min} = 1 - \sqrt{2}, when x = π