Given-A-p-2-q-2-r-2-2-pq-2-pr-2-qr-2-B-q-2-pr-p-2-q-2-r-2-If-p-q-r-0-then-A-2-4B-

Question Number 192440 by cortano12 last updated on 18/May/23

Given {\begin{cases} A = \frac{{(p^{2} + q^{2} + r^{2})}^{2}}{{(pq)}^{2} + {(pr)}^{2} + {(qr)}^{2}} \\ B = \frac{q^{2} - pr}{p^{2} + q^{2} + r^{2}} \end{cases}

If p + q + r = 0 then A^{2} - 4 B = ?

Answered by Frix last updated on 18/May/23

r = - (p + q) \Rightarrow A = 4 \land B = \frac{1}{2}

A^{2} - 4 B = 14

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