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given-eq-of-line-1-x-y-3-2-t-4-5-2-x-y-1-1-s-7-k-find-t-and-s-if-1-2-if-1-2-




Question Number 92301 by jagoll last updated on 06/May/20
given eq of line   (1) [ x,y ] = [3,−2] + t [4,−5]   (2) [x,y] = [1,1] + s [ 7,k ]   find t and s if (1) ∥ (2)  if (1) ⊥ (2)
giveneqofline(1)[x,y]=[3,2]+t[4,5](2)[x,y]=[1,1]+s[7,k]findtandsif(1)(2)if(1)(2)
Commented by jagoll last updated on 06/May/20
thank you both
thankyouboth
Commented by john santu last updated on 06/May/20
line (1) x=3+4t ⇒ t = ((x−3)/4)  y = −2−5t ⇒t =((−2−y)/5)  ⇒ ((x−3)/4) = ((−2−y)/5)   5x +4y −7 = 0  line (2) x = 1+7s ⇒s = ((x−1)/7)  y = 1+sk ⇒ s = ((y−1)/k)  ⇒ ((x−1)/7) = ((y−1)/k)  kx −7y +7−k =0  if parallel ⇒ ((−5)/4) = ((−k)/(−7))   k = − ((35)/4)  if perpendicular ⇒ (4/5) = (k/7)  k = ((28)/5)
line(1)x=3+4tt=x34y=25tt=2y5x34=2y55x+4y7=0line(2)x=1+7ss=x17y=1+sks=y1kx17=y1kkx7y+7k=0ifparallel54=k7k=354ifperpendicular45=k7k=285
Answered by mr W last updated on 06/May/20
(1)//(2):  ((−5)/4)=(k/7)  ⇒k=−((35)/4)    (1)⊥(2):  ((−5)/4)×(k/7)=−1  ⇒k=((28)/5)    please check question: t and s are  parameters and are of any values.  it is to find k=?
(1)//(2):54=k7k=354(1)(2):54×k7=1k=285pleasecheckquestion:tandsareparametersandareofanyvalues.itistofindk=?
Commented by jagoll last updated on 06/May/20
yes, t & s are parameters sir
yes,t&sareparameterssir
Commented by mr W last updated on 06/May/20

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