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Given-f-x-2-3-cos-x-sin-x-6x-pi-2-Find-lim-x-pi-6-f-x-




Question Number 126744 by bemath last updated on 24/Dec/20
  Given f(x)= ((2−(√3) cos x−sin x)/((6x−π)^2 ))   Find lim_(x→(π/6))  f(x) .
Givenf(x)=23cosxsinx(6xπ)2Findlimxπ6f(x).
Answered by liberty last updated on 24/Dec/20
 lim_(x→π/6) (((√3) sin x−cos x)/(12(6x−π))) = lim_(x→π/6) (((√3) cos x+sin x)/(72))   = (((√3) cos ((π/6))+sin ((π/6)))/(72)) = (((3/2)+(1/2))/(72)) = (1/(36))
limxπ/63sinxcosx12(6xπ)=limxπ/63cosx+sinx72=3cos(π6)+sin(π6)72=32+1272=136
Answered by bemath last updated on 24/Dec/20

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