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Given-f-x-7-cos-2x-2sin-2-x-find-f-10-x-




Question Number 114066 by john santu last updated on 17/Sep/20
Given f(x)=7+cos 2x+2sin^2 x  find f^((10)) (x) ?
Givenf(x)=7+cos2x+2sin2xfindf(10)(x)?
Commented by bemath last updated on 17/Sep/20
f(x)=7+1−2sin^2 x+2sin^2 x  f(x)=8 ⇒f^((10)) (x)= 0
f(x)=7+12sin2x+2sin2xf(x)=8f(10)(x)=0
Answered by Olaf last updated on 17/Sep/20
f(x) = 7+cos2x+2sin^2 x  f(x) = 7+cos2x+2((1−cos2x)/2)  f(x) = 8  f^((k)) (x) = 0
f(x)=7+cos2x+2sin2xf(x)=7+cos2x+21cos2x2f(x)=8f(k)(x)=0
Answered by 1549442205PVT last updated on 17/Sep/20
Since cos2x=1−2sin^2 x,cos2x+2sin^2 x  =1⇒f(x)=7+cos2x+2sin^2 x=8  ⇒f ′(x)=0⇒f^((n)) (x)=0∀n≥1,n∈N
Sincecos2x=12sin2x,cos2x+2sin2x=1f(x)=7+cos2x+2sin2x=8f(x)=0f(n)(x)=0n1,nN

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