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Given-f-x-f-x-2-x-R-If-0-2-f-x-dx-p-then-0-2020-f-x-2a-dx-for-a-Z-




Question Number 161256 by cortano last updated on 15/Dec/21
 Given f(x)=f(x+2), ∀x∈R   If ∫_0 ^2 f(x)dx= p then ∫_0 ^(2020) f(x+2a)dx=?   for a∈Z^+
Givenf(x)=f(x+2),xRIf20f(x)dx=pthen20200f(x+2a)dx=?foraZ+
Answered by talminator2856791 last updated on 17/Dec/21
     f(x+2a) = f(x+2a−2k) k ∈ Z   ⇒ f(x+2a) = f(x)      ∫_0 ^( 2020)  f(x+2a)dx = ∫_0 ^( 2020)  f(x)dx       ∫_0 ^( 2) f(x)dx = ∫_z ^( z+2) f(x)dx  z ∈ R      ∫_0 ^( 2020) f(x)dx = Σ_(k = 0) ^(1009)  ∫_(2k) ^( 2k+2)  f(x)dx       ⇒ ∫_0 ^( 2020)  f(x+2a)dx = 1010p
f(x+2a)=f(x+2a2k)kZf(x+2a)=f(x)02020f(x+2a)dx=02020f(x)dx02f(x)dx=zz+2f(x)dxzR02020f(x)dx=1009k=02k2k+2f(x)dx02020f(x+2a)dx=1010p

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