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Question Number 103515 by bemath last updated on 15/Jul/20
given f(x) = f(x+(π/6)) ∀x∈R  if ∫_0 ^(π/6) f(x)dx = T then ∫_π ^(7π/3) f(x+π)  dx ?
givenf(x)=f(x+π6)xRifπ/60f(x)dx=Tthen7π/3πf(x+π)dx?
Answered by bramlex last updated on 15/Jul/20
⇒∫_π ^(7π/3) f(x+π) dx = ∫_0 ^(4π/3) f(x)dx =  ∫_0 ^(8((π/6))) f(x) dx = 8T ■
7π/3πf(x+π)dx=4π/30f(x)dx=8(π6)0f(x)dx=8T◼

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